WebMar 29, 2024 · Transcript. Ex 5.3, 3 In an AP (i) Given a = 5, d = 3, an = 50, find n and Sn. Given a = 5 , d = 3 , an = 50 We know that an = a + (n – 1) d Putting values 50 = 5 + (n – 1) ×3 50 = 5 + 3n – 3 50 = 2 + 3n 50 – 2 = 3n 48 = 3n 48/3=𝑛 n = 16 Now we need to find Sn Sn = 𝒏/𝟐 (𝟐𝒂+ (𝒏−𝟏)𝒅) Putting n = 16, a = 5, d = 3 ... WebMar 31, 2024 · If in an A.P a=2 and d=3 then find s12 Advertisement Answer 12 people found it helpful misspayal66 Answer: S12 = n/2 (2a+ (12-1)d =12/6 (2*2+ (11*3) =2 (4+33) =2*37 =74 ans Find Math textbook solutions? Class 12 Class 11 Class 10 Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 NCERT Class 9 Mathematics 619 …
If Sn, denotes, the sum of the first n terms of an A.P. prove that S12 …
WebGiven that, a12 = 37, d = 3. As an = a + ( n − 1) d, a12 = a + (12 − 1)3. 37 = a + 33. a = 4. S n = n 2 [ a + a n] S n = 12 2 [ 4 + 37] S n = 6 ( 41) S n = 246. WebSolution: Given, Sₙ denotes the sum of first n terms of an AP. We have to prove that S₁₂ = 3 (S₈ - S₄). The sum of the first n terms of an AP is given by Sₙ = (n/2) [2a + (n-1)d] LHS: S₁₂ When n = 12, S₁₂ = (12/2) [2a + (12-1)d] S₁₂ = 6 [2a + 11d] S₁₂ = 12a + 66d RHS: 3 (S₈ - S₄) When n = 8, S₈ = (8/2) [2a + (8-1)d] S₈ = 4 [2a + 7d] S₈ = 8a + 28d moderna risk of blood clots
In an AP (i) Given a = 5, d = 3, an = 50 , find n and Sn. (ii) Given a ...
WebTo find out the common difference in an AP you can perform the following simple step. Explanation: Subtract the first term of the AP from the second term of the AP. d = a2 - a1 where d = common difference a2 = any term other than first term a1 = previous term For example; In the AP 3 , 9 , 15 , 21 , 27 , 33 Taking a1 = 3 Taking a2 = 9 WebApr 15, 2024 · The microwave irradiation of reaction mixtures was carried out in a Milestone Ethos Synth Microwave Synthesis Labstation. The chemical shift references for 1 H NMR spectra were the residual HDO (δ 4.79) in D 2 O or residual CHCl 3 (δ 7.26) in CDCl 3, while the 31 P NMR spectra were referenced against an external 85% H 3 PO 4 standard (δ 0 WebIf Sn denotes the sum of first n terms of an AP, then prove that S12 =3(S8−S4) Solution ∵ Sum of n terms of an AP, Sn = n 2[2a+(n−1)d] ⋯(i) ∴ S8 = 8 2[2a+(8−1)d] = 4(2a+7d) =8a+28d And S4 = 4 2[2a+(4−1)d]= 2(2a+3d) = 4a+6d N ow, S8−S4 =8a+28d−4a−6d= 4a+22d ⋯(ii) And S12 = 12 2[2a+(12−1)d] =6(2a+11d) modern arm chair ebay