How much work must be done by a force on 50kg
NettetA) -1100 J. B) -110 J. C) -140 J. D) -180 J. E) 120 J. B. Find the net work done by friction on a box that moves in a complete circle of radius on a uniform horizontal floor. The … NettetExample 1: Calculating the Work Done by a Force Acting on a Particle Where the Force and Position Are Given as Vectors. A particle moves in a plane in which ⃑ 𝑖 and ⃑ 𝑗 are perpendicular unit vectors. A force ⃑ 𝐹 = 9 ⃑ 𝑖 + ⃑ 𝑗 N acts on the particle. The particle moves from the origin to the point with position vector − 9 ⃑ 𝑖 + 6 ⃑ 𝑗 m.
How much work must be done by a force on 50kg
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Nettet7.3 Work-Energy Theorem. 50. (a) Calculate the force needed to bring a 950-kg car to rest from a speed of 90.0 km/h in a distance of 120 m (a fairly typical distance for a non … NettetAn old oaken bucket of mass 6.75 $\mathrm{kg}$ hangs in a well at the end of a rope. The rope passes over a frictionless pulley at the top of the well, and you pull horizontally on the end of the rope to raise the bucket slowly a distance of 4.00 $\mathrm{m} .$ (a) How much work do you do on the bucket in pulling it up?
NettetClick here👆to get an answer to your question ️ 2 How much work must be done by a force on 50 kg body in order to accelerate it from rest to 20 m/s in 10 s? (a) 103 J (b) 104J (c)2 x 103 J (d) 4 x 104J. Solve Study Textbooks … NettetThus, the car requires 25000 N of force to accelerate it. 23. what is the velocity of a 500kg elevator that has 400J of energy Answer: Answer the velocity of the elevator is 4ms . 24. how much force is required to accelerate a car with a mass of 500kg to 50 m/s Answer: 25000 N force is needed to accelerate a car with a mass of 500kg to 50 m/s :)
Nettet16. The octupos ride at the school fair cost 10.00 and the bump car cost 15.00 rodel has 100.00 and decides to spend it all on octupos and bump car write the equation for situation how many times can he ride on octupos and bump car; 17. A man in the street is bumped by a car immediate action to be taken; 18. Nettet17. apr. 2015 · Two point charges are located on the x-axis, q1 = -e at x=0 and q2 = +e at x=a. Find the work that must be done by an external force to bring a third point …
Nettet6. des. 2024 · How much work has been done by the force ? 9. The potential energy of a particle in a force field is U=\frac {A} {r^2}-\frac {B} {r} U = r2A − rB where A and B are …
Nettet16 timer siden · Michael Coutts-Trotter, husband of federal Labor minister Tanya Plibersek, was secretary of the NSW Department of Premier and Cabinet but will become head of Treasury when it is abolished. title count wowNettetDigested food is a source of potential energy. Alana summarized what happens when a ball sitting on top of a grassy hill rolls down the hill. The motionless ball has potential energy. Once the ball starts to roll down the hill, new kinetic energy is made. As the ball rolls across the grass, it slows down. title cost in michiganNettet21. des. 2024 · There are many instances in which the units used in real-life don't match the units used in physics, but work is not one of those... kind of. If you look at the work … title correction affidavit texasNettet21. jul. 2024 · This equation here. W = ∫ F ⋅ d x. is just the definition of the work W done by a force F along some path that you are performing the integral over. It is always applicable, as it is a definition. However this equation. W = Δ K. is only valid when W is the total work being performed on your object. title cotNettet20. feb. 2011 · Since friction is always an opposing force you subtract this from the 38.5KJ and get the 8455J mentioned. This is the kinetic energy so 1/2mv^2 and you then multiply both sides … title cost in texasNettetA: Given that Mass of the object, m=3 kg Initial speed of the object, u=10 m/s Final velocity , v=0…. Q: A car with a mass of 700 kg is moving with a speed of 20m/s. Calculate the kinetic energy of the…. Q: Apply the work equation to determine the amount of work done by the applied force An upward force…. Q: A 4-N force is applied to a 2 ... title countNettet22. des. 2024 · The good news it’s a simple law, describing a linear relationship and having the form of a basic straight-line equation. The formula for Hooke’s law specifically relates the change in extension of the spring, x , to the restoring force, F , generated in it: F = −kx F = −kx. The extra term, k , is the spring constant. title counter tops